x^2+12x-1436=0

Solution for x^2+12x-1436=0 equation:

x^2+12x-1436=0

a = 1; b = 12; c = -1436;
Δ = b2-4ac
Δ = 122-4·1·(-1436)
Δ = 5888
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

The end solution:

$\sqrt{\Delta}=\sqrt{5888}=\sqrt{256*23}=\sqrt{256}*\sqrt{23}=16\sqrt{23}$
$x_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(12)-16\sqrt{23}}{2*1}=\frac{-12-16\sqrt{23}}{2}
$
$x_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(12)+16\sqrt{23}}{2*1}=\frac{-12+16\sqrt{23}}{2}
$